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Process string characters using Byte arrays
[ All Languages » VB »  String]

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When you need to process each character in a string, you can assign the string to a byte array and iterate on its elements (remember: each Unicode character corresponds to two bytes). This approach is usually much faster because it saves a lot of Mid$ functions and, hence, a lot of temporary strings. Here is a very fast way to count the spaces in a string:

Click here to copy the following block
Dim b() as Byte, count As Integer
b() = source$
For i = 0 to UBound(b) Step LenB("A")
  If b(i) = 32 Then count = count + 1
Next

Note the unorthodox usage of the LenB() function: it returns 2 under VB4/32, VB5 and VB6, and 1 under VB4/16, so that you can use the same code fragment without the need for a #If compiler directive.
Beware: this technique might not work if you then localize your code for foreign countries that make use of the full Unicode character set.


Submitted By : Nayan Patel  (Member Since : 5/26/2004 12:23:06 PM)

Job Description : He is the moderator of this site and currently working as an independent consultant. He works with VB.net/ASP.net, SQL Server and other MS technologies. He is MCSD.net, MCDBA and MCSE. In his free time he likes to watch funny movies and doing oil painting.
View all (893) submissions by this author  (Birth Date : 7/14/1981 )


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